C

1. C(s)+ O2(g) ⎯⎯→ CO2(g) ΔH= –94 kJ
H2(g)+ O2(g) ⎯⎯→ 2 H2O(g) ΔH= –136 kJ
3C(s)+ 4 H2(g) ⎯⎯→ C3H8(g) ΔH= –24 kJ
Tentukan ΔH pada reaksi C3H8(g)+ 5 O2(g) ⎯⎯→3 CO2(g)+ 4 H2O(g)!
Jawab:
C(s)+ O2(g) ⎯⎯→ CO2(g) ΔH= –94 kJ
H2(g)+ O2(g) ⎯⎯→ 2 H2O(g) ΔH= –136 kJ
C3H8(g) ⎯⎯→ 3C(s)+ 4 H2(g) ΔH= 24 kJ (reaksi di balik)
3C(s)+ 3O2(g) ⎯⎯→ 3CO2(g) ΔH= –282 kJ x 3 ( reaksi dikali 3)
H2(g)+ O2(g) ⎯⎯→ 2 H2O(g) ΔH= –136 kJ
C3H8(g) ⎯⎯→ 3C(s)+ 4 H2(g) ΔH= 24 kJ (reaksi di balik)
3C(s)+ 3O2(g) ⎯⎯→ 3CO2(g) ΔH= –282 kJ ( reaksi dikali 3)
2H2(g)+ 2O2(g) ⎯⎯→ 4 H2O(g) ΔH= –272 kJ (reaksi dikali 2)
C3H8(g) ⎯⎯→ 3C(s)+ 4 H2(g)
ΔH= 24 kJ (reaksi di balik)
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C3H8(g)+ 5 O2(g) ⎯⎯→3 CO2(g)+ 4 H2O(g)
ΔH=.......... kJ