LAPORAN PRAKTIKUM OPERASI TEKNIK KIMIA-1 ROTARY DRUM VACUUM FILTER OLEH: POLITEKNIK NEGERI BANDUNG D-IV TEKNIK KIMIA PRODUKSI BERSIH 2019 I. TUJUAN PRAKTIKUM Setelah melakukan praktikum ini, kami diharapkan dapat: 1. Memahami pengoperasian rotary drum filter, mulai dari prosedur start up, operasi normal, sampai shut down. 2. Mengamati karakter proses operasi filtrasi kontinyu memakai alat rotary drum filter. 3. Mendapatkan hubungan antar variabel yang mempengaruhi pengoperasian rotary drum filter dengan persamaan karakteristik yang telah tersedia di literatur. 4. Mencari konstanta karakteristik untuk operasi ini dengan pengolahan data praktikum. II. TABEL DATA PENGAMATAN a. Kondisi Alat - Keliling drum (K) = 1,5857 m - Lebar screen (L): 40,4 cm = 0,404 m - Filter area = K x L = 0,641 m2 - Panjang busur drum yang tercelup ke dalam slurry (K’) = 0,4857 m - Fraksi drum yang tercelup = K’/K = 0,4857 m/1,6014 m = 0,3063 m - Panjang dead zone (Ldz) = 0,14 m - Tekanan Operasi (-βπ) = -0,8 bar = 80000 Pascal - 1 cm tinggi filtrat (H filtrat) setara dengan volume filtrat (V) = 2,28 Liter = 2,28 x 10-3 m3 b. Hubungan antara Volume Filtrat dengan Time Cycle Run 1 2 3 4 5 Skala 10 20 30 40 50 Periode 19,4 17,6 27,28 27,3 27,1 Nomor H Filtrat Data (m) 1 0 0 20,13 14,46 5,87 17,11 28,07 2 0,02 4,56 x 10-3 24,84 41,47 17,36 36,13 62,63 3 0,04 9,12 x 10-3 27,84 70,45 36,23 50,59 84,60 4 0,06 13,68 x 10-3 37,84 92,9 63,69 65.65 108,14 5 0,08 18,24 x 10-3 65,84 178,55 89,68 82,69 68,89 6 0,1 22,8 x 10-3 68,84 141 114,22 99,36 147,66 V filtrat (m) Waktu Pengisian Tangki Filtrat (S) Rata-rata c. Hubungan antara Tebal Cake dengan Periode Putaran RUN Waktu pelepasan cake pada detik ke- 1 2 3 4 5 19,14 17,6 19,41 18,85 18,26 100 138 134,63 122,2 166,41 80,86 120,4 115,22 103,35 148,15 2,592 4,776 5,019 4,597 5,980 2,701 4,832 5,102 4,653 6,067 1070 1070 1040 1030 1040 0,00025 0,00045 0,00050 0,00045 0,00055 Waktu pelepsan cake pada 10 cm filtrat (tp,s) Waktu Percobaaan (tp, detik) Massa Total Cake (M1, kg) Massa Total Cake + Air (M2, kg) Massa Jenis Cake (kg/m3) Volume Total Cake (Vcake, m3) Rata-rata d. Karakter Filtrat RUN 1 2 3 4 5 Rata-rata tfiltrat (π ) 0,99 0,98 0,92 0,73 0,59 0,842 1070 1070 1040 1030 1040 1050 m (gram) V (ml) π (ππ/ π 3) e. Penentuan Cs Berat cawan penguap kosong = 41,2 gram Berat basah slurry + cawan penguap = 42,7 gram Berat basah slurry = 1,5 g = 0,0015 Berat kering slurry + cawan penguap = 41,6 gram Berat kering slurry = 0,4 gram = 0,0004 kg Cx = πππππ πππππ πππππ ππππππ = π,ππππ ππ π,ππππ ππ = π, πππ Berat basah cake + cawan penguap = 41,8 gram Berat basah cake = 2,1 g = 0,0021 kg Berat kering cake + cawan penguap = 40,4 gram Berat kering cake = 0,7 gram = 0,0007 kg πππππ πππππ ππππ m = πππππ ππππππ ππππ = III. π,ππππ ππ π,ππππ ππ =π Pengolahan Data ο· Keliling drum (K) = 1,5857 m ο· Lebar Screen = 40,5 cm = 0,404 m ο· Filter Area = K x L = 0,641 m2 ο· Panjang busur drum yg tercelup kedalam slurry (K’) = 0,4857 m ο· Fraksi drum yang tercelup = K’ / K = 0,3063 ο· Massa Jenis Cake πcake = (1-π) πair π= π2−π1 π1 ο Run 1 π2−π1 πcake = (1- π1 ) πair 2,701−2,592 πcake = (1- 2,592 ) 997 kg/m3 = 955,126 kg/m3 ο Run 2 π2−π1 πcake = (1- π1 ) πair 4,832−4,776 πcake = (1- ) 997 kg/m3 = 985,036 kg/m3 4,776 ο Run 3 π2−π1 πcake = (1- π1 ) πair 5,102−5,019 πcake = (1- 5,019 ) 997 kg/m3 = 980,051 kg/m3 ο Run 4 π2−π1 πcake = (1- π1 ) πair 4,653−4,597 πcake = (1- 4,597 ) 997 kg/m3 = 985,036 kg/m3 ο Run 5 π2−π1 πcake = (1- π1 ) πair 6,067−5,980 πcake = (1- ο· 5,980 ) 997 kg/m3 = 982,045 kg/m3 Volume Total Cake (V cake) V cake = π ππππ π ππππ ο Run 1 V cake = π ππππ π ππππ = 2,592ππ ππ π3 955,126 = 2,714 π₯ 10-3 m3 ο Run 2 V cake = π ππππ π ππππ 4,776 ππ = 985,036 ππ/π3 = 4,849 π₯ 10-3 m3 ο Run 3 V cake = π ππππ π ππππ 5,019ππ = 980,051 ππ/π3 = 5,121 π₯ 10-3 m3 ο Run 4 π ππππ V cake = π ππππ 4,597 ππ = 985,036 ππ/π3 = 4,667 π₯ 10-3 m3 ο Run 5 π ππππ V cake = ο· π ππππ 5,980 ππ = 982,045 ππ/π3 = 6,089 π₯ 10-3 m3 Viskositas tfiltrat rata-rata = 0,99+0,98+0,92+0,73+0,59 5 = 0,842 π tair = 0,26 s η air = 0,899 cp πair = 997 kg/m3 η filtrat = η air . ρ filtrat . t filtrat π πππ. π‘ πππ η filtrat = ο· 0,899 ππ . 1050 ππ 997 π3 0,842 π .0,26 π = 3,066 cp Penentuan Cs Cx = πππππ πππππ πππππ ππππππ = π,ππππ ππ π,ππππ ππ πππππ πππππ ππππ m = πππππ ππππππ ππππ = π.πΆπ₯ Cs = 1−π.πΆπ₯ = ο· ππ . π3 806,74 = π, πππ π,ππππ ππ π,ππππ ππ ππ π₯ π3 0,6820 1−1,0579 π₯ 0,6820 =π = 1975,4850 kg/m3 Penentuan Z Z=( Z=( Φ= 2.π.(−βπ) π . πΆπ ) 2 . 0,3063 . ( 80000 ππ/ππ 2) 0.003066 π π΄ . π‘π 1 Φ2 = (πΌ)( ππ . ππ =[ 1975,4850ππ/π3 2.π. (−βπ) π‘π . π . πΌ . πΆπ 2.π. (−βπ) π . πΆπ 1 )(π‘π) ]1/2 ) = 8091.352 π3/kg.s ο· Penentuan flow rate (Φ) π Φ = π΄. π‘π ο Run 1 Φ = 0,0228 π3 = 5,170 x 10-4 m/s 0,6406 π2 π₯ 68.84 π ο Run 2 Φ = 0,0228 π3 0,6404 π2 . 141 π = 2,525 x 10-4 m/s ο Run 3 Φ = 0,0228 π3 0,6404 π2 . 114,22 π = 3,117 x 10-4 m/s ο Run 4 Φ = 0,0228 π3 0,6404 π2 . 99.36 π = 3,583 x 10-4 m/s ο Run 5 Φ = 0,0228 π3 0,6404 π2 . 147,66 π = 2,411 x 10-4 m/s ο Rata-rata Φ = 3.890 x 10-4 ο· Penentuan πΆ 1π₯π πΌ= Φ x tc ο Run 1 πΌ= 8091.352 m3/kg. s = 227347,242 π/ππ (5,170 x 10 − 4 π/π )2 π₯ 68.84 π ο Run 2 πΌ= 8091.352 m3/kg. s = 227269,209 π/ππ ( 2,525 x 10 − 4 π/π )2 π₯ 141 π ο Run 3 πΌ= 8091.352 m3/kg. s = 227270,013 π/ππ (3,117 x 10 − 4 π/π )2 π₯ 114,22 π ο Run 4 πΌ= 8091.352 m3/kg. s = 227280,776 π/ππ (3,583 x 10 − 4 π/π )2 π₯ 99,36 π ο Run 5 πΌ= 8091.352 m3/kg. s = 227279,900 π/ππ (2,411 x 10 − 4 π/π )2 π₯ 147,66 π ο Rata-rata πΌ= ο· Nilai Tebal Cake βπΏ ππππ = πππππ πΏ−πΏππ§ π΄.( ) πΏ π₯ π‘π π‘π L = Lebar Screen = 0,404 m Ldz = panjang dead zone = 0,14 m ο Run 1 βπΏ ππππ = 2,714 π₯ 10−3 m3 0,404−0,14 ) 0,404 0,6406 π2.( π₯ 68.84 π π‘π ο Run 2 βπΏ ππππ = 4,849 π₯ 10−3 m3 0,404−0,14 0,6406 π2.( ) 0,404 π₯ 141 π π‘π ο Run 3 βπΏ ππππ = 5,121 π₯ 10−3 m3 0,404−0,14 ) 0,404 0,6406 π2.( π₯ 114,22 π π‘π ο Run 4 βπΏ ππππ = 4,667 π₯ 10−3 m3 0,404−0,14 ) 0,404 0,6406 π2.( π₯ 99,36 π π‘π ο Run 5 βπΏ ππππ = ο Rata-rata 6,089 π₯ 10−3 m3 0,404−0,14 0,6406 π2.( ) 0,404 π₯ 147,66 π π‘π